-3p^2+800p+10000=0

Solution for -3p^2+800p+10000=0 equation:

-3p^2+800p+10000=0

a = -3; b = 800; c = +10000;
Δ = b2-4ac
Δ = 8002-4·(-3)·10000
Δ = 760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{760000}=\sqrt{40000*19}=\sqrt{40000}*\sqrt{19}=200\sqrt{19}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-200\sqrt{19}}{2*-3}=\frac{-800-200\sqrt{19}}{-6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+200\sqrt{19}}{2*-3}=\frac{-800+200\sqrt{19}}{-6}
$